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J & K CET Engineering J and K - CET Engineering Solved Paper-2015

  • question_answer
    Energy of activation of forward reaction for an endothermic process is 90 kJ. If enthalpy change for the reaction is 50 kJ then activation  energy for backward reaction will be

    A)  40 kJ

    B)  140 kJ

    C)  90 kJ

    D)  50 kJ

    Correct Answer: A

    Solution :

     Given, \[{{E}_{f}}=90\,kJ\] \[{{E}_{b}}=?\] \[\Delta \Eta =50\,kJ\] \[\Delta \Eta ={{E}_{f}}-{{E}_{b}}\] \[50=90-{{E}_{b}}\] \[{{E}_{b}}=(90-50)kJ\] \[{{E}_{b}}=40\,kJ\]


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