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J & K CET Engineering J and K - CET Engineering Solved Paper-2015

  • question_answer
    Molar enthalpy change for melting of ice is 6 kJ/mol. Then the internal energy change (in kJ/mol) when 1 mole of water is converted into ice at 1 atm at \[0{{\,}^{o}}C\]is

    A) \[RT/1000\]

    B)  6

    C)  \[6-(RT/1000)\]

    D)  \[6+(RT/1000)\]

    Correct Answer: B

    Solution :

     Given,\[\Delta H=6\,kJ/mol\] \[\Delta U=?\] \[{{H}_{2}}O(l)Ice(s)\] \[\because \] \[\Delta H=\Delta U+\Delta {{n}_{g}}RT\] Here, \[\Delta {{n}_{g}}=0\] \[\therefore \] \[\Delta H=\Delta U\] \[\Rightarrow \] \[\Delta U=6\,kJ/mol\]


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