A) zero
B) \[\frac{\pi }{4}\]
C) \[\frac{\pi }{2}\]
D) \[\pi \]
Correct Answer: A
Solution :
In a series LCR circuit the phase angle is given by \[\tan \phi =\frac{\omega L-\frac{1}{\omega C}}{R}\] At resonance \[\omega L-\frac{1}{\omega C},\]then\[\tan \,\phi =0,\]i.e., \[\,\phi =0\]You need to login to perform this action.
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