A) \[{{H}_{2}}O\]
B) \[{{H}^{+}}\]
C) \[F{{e}^{2+}}\]
D) \[MnO_{2}^{-}\]
Correct Answer: C
Solution :
Hence, in this reaction\[F{{e}^{2+}}\]acts as a reducing agent. It reduces\[MnO_{4}^{-}\]to\[M{{n}^{2+}}\].You need to login to perform this action.
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