A) \[\Delta H=T\Delta S\]
B) \[\Delta H=0\]
C) \[\Delta H=\Delta E\]
D) \[\Delta E=0\]
Correct Answer: A
Solution :
\[{{H}_{2}}O(l){{H}_{2}}O(g)\] Since, the process is in equilibrium. Hence, \[\Delta G=0.\] \[\because \] \[\Delta G=\Delta H-T.\Delta S\] \[0=\Delta H-T.\Delta S\] \[\therefore \] \[\Delta H=T.\Delta S\]You need to login to perform this action.
You will be redirected in
3 sec