A) 12 g of\[^{12}C{{O}_{2}}\]
B) 22.4 L\[^{12}C{{O}_{2}}\]at room temperature
C) 44 g of \[^{12}C{{O}_{2}}\]
D) 12 moles of \[^{12}C{{O}_{2}}\]
Correct Answer: C
Solution :
Avogadro number\[(6.023\times {{10}^{23}})\]of carbon atoms are present in 44 g of\[^{12}C{{O}_{2}}\].
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