A) The equivalent mass of\[KMn{{O}_{4}}\]in alkaline medium is molar mass divided by five.
B) The equivalent mass of\[KMn{{O}_{4}}\]in strongly alkaline medium is molar mass divided by three.
C) The equivalent mass of\[KMn{{O}_{4}}\]in neutral medium is molar mass divided by three.
D) The equivalent mass of\[KMn{{O}_{4}}\]in weakly acidic medium is molar mass divided by three.
Correct Answer: B
Solution :
The equivalent mass of\[KMn{{O}_{4}}\]in strongly alkaline medium is molar mass divided by three. \[MnO_{4}^{-}+3{{e}^{-}}+2{{H}_{2}}O\xrightarrow[{}]{{}}Mn{{O}_{2}}+4O{{H}^{-}}\] \[\therefore \] \[Eq.\,wt=\frac{Mol.\,wt}{3}\]
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