A) 12 h
B) 6 h
C) 3 h
D) 4 days
Correct Answer: C
Solution :
From Keplers third law \[{{T}^{2}}\propto {{R}^{3}}\] Or \[T\propto {{R}^{3/2}}\] \[\therefore \] \[\frac{{{T}_{1}}}{{{T}_{2}}}={{\left( \frac{{{R}_{1}}}{{{R}_{2}}} \right)}^{3/2}}\] \[\frac{{{T}_{1}}}{{{T}_{2}}}={{\left( \frac{4{{R}_{1}}}{{{R}_{1}}} \right)}^{3/2}}\] \[{{T}_{2}}=\frac{{{T}_{1}}}{8}=\frac{29}{8}=3h\]
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