A) \[w\]
B) \[\frac{w}{2}\]
C) \[\frac{w}{4}\]
D) \[4w\]
Correct Answer: C
Solution :
The elastic limit of steel = support the maximum B load Load\[=Y\alpha \Delta t\pi {{r}^{2}}\] Then, \[w=Y\pi \,\alpha \,\Delta t{{R}^{2}}\] ...(i) load \[w=Y\pi \alpha \Delta t{{\left( \frac{R}{2} \right)}^{2}}\] \[=\frac{y\pi \,\alpha \,\Delta t{{R}^{2}}}{4}=\frac{w}{4}\]
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