J & K CET Medical J & K - CET Medical Solved Paper-2012

  • question_answer
    A block is placed on a plane inclined at\[12{}^\circ \]to the horizontal. What is the, maximum value of coefficient of static friction for which the block slides down the plane?

    A)  \[tan\text{ }12{}^\circ \]          

    B)  \[\text{cos }12{}^\circ \]

    C)  \[\text{sin }12{}^\circ \]          

    D)  None of these

    Correct Answer: A

    Solution :

     Coefficient of static friction \[{{\mu }_{s}}=\tan {{\theta }_{s}}\] \[{{\mu }_{s}}=\tan 12\]


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