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J & K CET Medical J & K - CET Medical Solved Paper-2012

  • question_answer
    The equation describing the motion of a simple harmonic oscillator along the\[x\]axis is given as \[x=A\cos (\omega t+\phi )\]. If at time\[t=0,\]the oscillator is at\[x=0\]and moving in the negative\[x-\]direction, then the phase angle\[\phi \]is

    A)  \[\frac{\pi }{2}\]

    B)  \[-\frac{\pi }{2}\]

    C)  \[\pi \]

    D)  \[0\]

    Correct Answer: A

    Solution :

     \[x=A\cos (\omega t+\phi )\] Let \[t=0,\text{ }x=0\] \[0=\cos \phi \] \[\cos \frac{\pi }{2}=\cos \phi \] \[\theta =\frac{\pi }{2}\]


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