A) 0.25 mm
B) 0.1 mm
C) 0.5 mm
D) 0.025 mm
Correct Answer: D
Solution :
Fringe width\[\beta =\frac{\lambda D}{d}\] \[=\frac{(5000\times {{10}^{-10}})\times 1}{2\times {{10}^{-3}}}\] \[=2500\times {{10}^{-7}}m\] \[=0.25\text{ }mm\]
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