A) unimolecular
B) bimolecular
C) trimolecular
D) rate depends on concentration of incoming nucleophile
Correct Answer: A
Solution :
A nucleophilic substitution reaction proceeds through\[{{S}_{N}}1\]mechanism, so the reaction is unimolecular. \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-Br\xrightarrow[{}]{Slow}C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{{{C}^{+}}}}}\,+B{{r}^{-}}\] \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{{{C}^{+}}}}}\,-O{{H}^{-}}\xrightarrow[{}]{Fast}C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-OH\] \[Rate\propto [3{}^\circ alkyl\text{ }halide]\]
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