A) 6
B) 4
C) 0
D) 3
Correct Answer: D
Solution :
Let oxidation number of\[Co\]be\[x\]; Oxidation number of\[{{H}_{2}}O=0;\] Oxidation number of\[CN=-1\] Therefore \[{{[Co(CN)({{H}_{2}}O){{(en)}^{2}}]}^{2}}\] \[x+2(0)-1=+2\] \[x-1=+2=+3\text{ }or\text{ }3\] Hence, coordination number of\[Co\]is 3.You need to login to perform this action.
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