A) \[{{C}_{2}}{{H}_{5}}I\]
B) \[C{{H}_{3}}I\]
C) \[CH{{I}_{3}}\]
D) \[C{{H}_{2}}{{I}_{2}}\]
Correct Answer: C
Solution :
Formation of iodoform takes place. \[C{{H}_{3}}C{{H}_{2}}OH+{{I}_{2}}\xrightarrow[{}]{Oxidation}C{{H}_{3}}CHO\xrightarrow[{}]{{{I}_{2}}/O{{H}^{-}}}\]\[C{{l}_{3}}CHO\xrightarrow[{}]{O{{H}^{-}}}CH{{I}_{3}}+HCO{{O}^{-}}\]
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