A) benzoic acid
B) aniline
C) benzyl amine
D) benzonitrile
Correct Answer: C
Solution :
\[\underset{benzoyl\text{ }chloride}{\mathop{{{C}_{6}}{{H}_{5}}COCl}}\,\xrightarrow[-HCl]{N{{H}_{3}}}\underset{Benzamide}{\mathop{{{C}_{6}}{{H}_{5}}CON{{H}_{2}}}}\,\] \[\xrightarrow[-{{H}_{2}}O]{{{P}_{2}}{{O}_{5}}}\underset{benzonitrile}{\mathop{{{C}_{6}}{{H}_{5}}CN}}\,\xrightarrow[{{H}_{2}}]{Ni}\underset{benzyla\min e}{\mathop{{{C}_{6}}{{H}_{5}}C{{H}_{2}}N{{H}_{2}}}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
