A) 1300 m/s
B) 2600 m/s
C) 1898 m/s
D) 650 m/s
Correct Answer: C
Solution :
\[{{v}_{rms}}={{v}_{s}}\sqrt{\frac{3}{\gamma }}\] Also, \[\gamma =\frac{{{C}_{p}}}{{{C}_{v}}},R={{C}_{p}}-{{C}_{v}}\] Given, \[R=1.98cal\,{{K}^{-1}}mo{{l}^{-1}},\] \[{{C}_{p}}=6.84\,cal\,{{K}^{-1}}mo{{l}^{-1}},\] \[{{C}_{p}}=4.86\,cal\,{{K}^{-1}}mo{{l}^{-1}},\gamma =1.41\]
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