A) \[5.024\times {{10}^{-8}}Wb/{{m}^{2}}\]
B) \[6.024\times {{10}^{-8}}Wb/{{m}^{2}}\]
C) \[7.024\times {{10}^{-8}}Wb/{{m}^{2}}\]
D) \[8.024\times {{10}^{-8}}Wb/{{m}^{2}}\]
Correct Answer: A
Solution :
\[B={{\mu }_{0}}nI\] Given, \[{{\mu }_{0}}=4\pi \times {{10}^{-7}},n=5\,cm,l=0.8A\] \[B=5.024\times {{10}^{-8}}Wb/{{m}^{2}}\]
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