A) \[2\times {{10}^{-3}}V\]
B) \[1\times {{10}^{-3}}V\]
C) \[1\times {{10}^{-4}}V\]
D) \[2\times {{10}^{-4}}V\]
Correct Answer: C
Solution :
\[e=-Bvl\] Given, \[l=5cm=5\times {{10}^{-2}}m,v=2m/s,\] \[B={{10}^{-3}}Wb/{{m}^{2}}\] \[e={{10}^{-3}}\times 2\times 5\times {{10}^{-2}}\] \[e=10\times {{10}^{-5}}V\] \[e=1\times {{10}^{-4}}V\]
You need to login to perform this action.
You will be redirected in
3 sec
