A) highly acidic
B) neutral
C) highly basic
D) slightly acidic
Correct Answer: B
Solution :
We know that \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] So, \[\underset{\begin{smallmatrix} {{H}_{2}}S{{O}_{4}} \\ 1\times 100 \end{smallmatrix}}{\mathop{{{N}_{1}}{{V}_{1}}}}\,=\underset{\begin{smallmatrix} NaOH \\ {{N}_{2}}\times 100 \end{smallmatrix}}{\mathop{{{N}_{2}}{{V}_{2}}}}\,\] \[{{N}_{2}}=1\] \[\because \]100 mL of\[1\text{ }N\,{{H}_{2}}S{{O}_{4}}\]will neutralize 100 mL of\[1N\text{ }NaOH\]so, the solution will be neutral.
You need to login to perform this action.
You will be redirected in
3 sec
