J & K CET Medical J & K - CET Medical Solved Paper-2014

  • question_answer
    Light from a point source in air falls on a spherical glass surface (n = 1.67 and radius of curvature =25 cm). The distance of the light source from the glass surface is 95 cm. At what position, the image is formed?

    A)  75.45 cm        

    B)  90.50 cm

    C)  105.25 cm       

    D)  99.40 cm

    Correct Answer: D

    Solution :

     From the formula of refraction at the spherical surface, \[\frac{{{n}_{2}}}{v}-\frac{{{n}_{1}}}{u}=\frac{{{n}_{2}}-{{n}_{1}}}{R}\] \[\frac{1.67}{v}=\frac{0.67}{25}-\frac{1}{95}\] \[=0.0268-0.0105\] \[\frac{1.67}{v}=0.0163\] \[v=\frac{1.67}{0.0163}=102.45\approx 99.4\]


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