A) 15.48 m
B) 18.64 m
C) 22.13 m
D) 27.55 m
Correct Answer: D
Solution :
\[u=42\times \frac{5}{18}=11.66\,m/s\] and \[v=0\] So, \[{{S}_{1}}=6m\] when, \[u=90\times \frac{5}{18}=25m/s\] and \[v=0\] Then, \[{{S}_{2}}=?\] For first case \[\Rightarrow \] \[{{v}^{2}}={{u}^{2}}+2a{{s}_{1}}\] \[0={{(11.66)}^{2}}+2a\times 6\] \[({{s}_{1}}=6m)\] \[a=\frac{-11.66\times 11.66}{12}\] \[a=-11.33m/{{s}^{2}}\] For second case \[{{v}^{2}}={{u}^{2}}+2a{{s}_{2}}\] \[0={{(25)}^{2}}+2(-11.33)\times {{s}_{2}}\] \[{{s}_{2}}=\frac{625}{2\times 11.33}=27.5\,m\]
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