A) \[2.46\times {{10}^{-4}}V\]
B) \[6.28\times {{10}^{-4}}V\]
C) \[5.76\times {{10}^{-5}}V\]
D) \[4.92\times {{10}^{-4}}V\]
Correct Answer: A
Solution :
In the case of rotating wheel in a normal magnetic field induced emf\[=\frac{1}{2}\omega B{{R}^{2}}\] \[e=\frac{1}{2}\times 2\pi \left( \frac{120}{60} \right)\times 0.8\times {{10}^{-4}}\times {{(0.7)}^{2}}\] \[=2\pi \times 0.8\times {{10}^{-4}}\times 0.49=2.46\times {{10}^{-4}}V\]
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