A) 1500.5 J
B) 1687.5 J
C) 2000.7J
D) 1350.0 J
Correct Answer: B
Solution :
KE of rotating cylinder\[=\frac{1}{2}I{{\omega }^{2}}\] \[I=\frac{M{{R}^{2}}}{2}\] [for solid cylinder] \[=15\times 0.09\] \[=1.35kg/{{s}^{2}}\] \[\Rightarrow \]So \[KE=\frac{1}{2}\times 1.35\times {{(50)}^{2}}\] \[=1687.53\]
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