A) 0.654 T
B) 0.336 T
C) 1.576 T
D) 0.939 T
Correct Answer: B
Solution :
Here weight of the wire is balanced by the extended magnetic force. So, \[Bil=mg\] \[B=\frac{mg}{il}\] \[=\frac{300\times {{10}^{-3}}\times 10}{3.5\times 2.5}=0.34\,T\]
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