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J & K CET Medical J & K - CET Medical Solved Paper-2014

  • question_answer
    The neutral point on potentiometers scale for two cells of EMF 2.1 and E volts is observed at distances 40 cm and 56 cm respectively. The value of E is

    A)  2.10V             

    B)  2.94V

    C)  1.50V             

    D)  1.20V

    Correct Answer: B

    Solution :

     For equating emf of two cells \[\frac{{{e}_{1}}}{{{e}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\] \[\frac{2.1}{E}=\frac{40}{56}\] \[E=\frac{2.1\times 56}{40}=2.94V\]


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