A) 46%
B) 40%
C) 30%
D) 80%
Correct Answer: A
Solution :
\[Q\propto {{T}^{4}}\Rightarrow \frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\] If\[{{T}_{1}}=T\]then\[{{T}_{2}}=T+\frac{10}{100}T=1.1T\] \[\frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{T}{1.1T} \right)}^{4}}\Rightarrow {{Q}_{2}}=1.46{{Q}_{1}}\] % increase in energy \[=\left( \frac{{{Q}_{2}}-{{Q}_{1}}}{{{Q}_{1}}} \right)%=46%\]
You need to login to perform this action.
You will be redirected in
3 sec
