J & K CET Medical J & K - CET Medical Solved Paper-2014

  • question_answer
    A compound microscope has a magnification of 30. The focal length of the eye-piece is 5 cm. If the final image is formed at the least distance of distinct vision (25 cm) the magnification produced by the objective is

    A)  10   

    B)  7.5    

    C)  5     

    D)  15

    Correct Answer: C

    Solution :

     \[m=30\] \[{{f}_{e}}=5\,cm\] \[m={{m}_{o}}\times {{m}_{e}}\] \[m={{m}_{o}}\times \left( 1+\frac{D}{{{f}_{e}}} \right)\] \[30={{m}_{o}}\left( 1+\frac{25}{5} \right)\] \[\Rightarrow \] \[{{m}_{o}}=5\]


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