J & K CET Medical J & K - CET Medical Solved Paper-2014

  • question_answer
    A stone of mass 0.05 kg is thrown vertically upwards. What is the direction and magnitude of the net force on the stone during its upward motion?

    A)  0.49 N vertically downward direction

    B)  0.49 N vertically upwards direction

    C)  0.05 N vertically downwards direction

    D)  9.8 N vertically upwards direction

    Correct Answer: A

    Solution :

     Weight of the stone\[=0.05\times 9.8\] = 0.49 [ vertically downward]


You need to login to perform this action.
You will be redirected in 3 sec spinner