A) \[Cl{{O}_{2}}+{{H}_{2}}S{{O}_{4}}\]
B) \[C{{l}_{2}}{{O}_{7}}+{{H}_{2}}S{{O}_{4}}\]
C) \[HCl{{O}_{4}}+{{H}_{2}}S{{O}_{4}}\]
D) \[C{{l}_{2}}{{O}_{6}}+{{H}_{2}}S{{O}_{4}}\]
Correct Answer: D
Solution :
\[HCl{{O}_{4}}.2{{H}_{2}}O+\underset{(Fu\min g)}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\xrightarrow{{}}\underset{\begin{smallmatrix} Dichlorine \\ hexaoxide \end{smallmatrix}}{\mathop{C{{l}_{2}}{{O}_{6}}}}\,+{{H}_{2}}S{{O}_{4}}\] \[HCl{{O}_{4}}\]corresponding to\[HCl{{O}_{4}}.2{{H}_{2}}O\]distined at low pressure in presence of fuming sulphuric acid avoiding all contact with oxidisable substances to obtain the anhydrous acid.
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