A) \[-300\,R\,in\,10\]
B) \[300\,R\,in\,10\]
C) \[18\]
D) \[-18\]
Correct Answer: A
Solution :
Given, \[{{V}_{1}}=2L\] \[{{V}_{2}}=20\text{ }L\] \[T=300\text{ }K\] \[{{p}_{2}}=1\text{ }bar\] Work done for ideal gas expands isothermally and reversibly \[\Rightarrow \] \[W=-2303\,RT\log \frac{{{V}_{2}}}{{{V}_{1}}}\] \[\Rightarrow \] \[W=-\,RT\,in\frac{{{V}_{2}}}{{{V}_{1}}}\] \[\Rightarrow \] \[W=-\,R\times 300\,in\frac{20}{2}\] \[\Rightarrow \] \[W=-300\,\,R\,in\,10\]
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