A) 0
B) \[v/2\]
C) \[v/\sqrt{2}\]
D) \[(\sqrt{2})v\]
Correct Answer: A
Solution :
Let velocity of one pendulum is \[{{v}_{1}}={{v}_{0}}\cos (\omega t+{{\phi }_{1}})\] Velocity of the other pendulum is \[{{v}_{2}}={{v}_{0}}\cos (\omega t+{{\phi }_{2}})\] According to the question, \[{{\phi }_{2}}-{{\phi }_{1}}=45{}^\circ \] Clearly, \[|{{v}_{1}}{{|}_{\max }}=|{{v}_{2}}{{|}_{\max }}={{v}_{0}}=v\] Thus, \[x=0\]
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