A) 6.5%
B) 12.5%
C) 25.5%
D) 33.3%
Correct Answer: B
Solution :
Amount of radioactive material left is \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] where \[n=\]number of half lives. \[=3\] \[{{N}_{0}}=\]original amount of the radioactive material. \[\Rightarrow \] \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{3}}=\frac{{{N}_{0}}}{8}\] \[=\frac{100}{8}%\]of\[{{N}_{0}}=125%\]of\[{{N}_{0}}\]
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