J & K CET Medical J & K - CET Medical Solved Paper-2015

  • question_answer
    The carbon resistor has the color band sequence of green, orange, blue and silver. The value of resistance will be

    A)  \[64\times {{10}^{7}}\pm 20%\,\Omega \]

    B)  \[53\times {{10}^{6}}\pm 20%\,\Omega \]

    C)  \[64\times {{10}^{7}}\pm 10%\,\Omega \]

    D)  \[53\times {{10}^{6}}\pm 10%\,\Omega \]

    Correct Answer: D

    Solution :

     Figure and multiplier corresponding to the given colours are
    Colour Figure Multiplier
    Green 5 \[{{10}^{5}}\]
    Orange 3 \[{{10}^{3}}\]
    Blue 6 \[{{10}^{6}}\]
    Tolerance corresponding to silver is 10%. Thus, the value of resistance is \[R=53\times {{10}^{6}}\pm 10%\,\Omega \]


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