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J & K CET Medical J & K - CET Medical Solved Paper-2015

  • question_answer
    For a reaction,\[C(s)+C{{O}_{2}}(g)\xrightarrow{{}}2CO(g);\]the partial pressure of\[C{{O}_{2}}\]and\[CO\]are 4 and 8 atm, respectively.\[{{K}_{p}}\]for the reaction is

    A)  0.5     

    B)  2      

    C)  16     

    D)  4

    Correct Answer: C

    Solution :

     \[C(s)+C{{O}_{2}}(g)\xrightarrow[{}]{{}}2CO(g)\] Applying the law of mass action \[{{K}_{p}}=\frac{{{({{p}_{CO}})}^{2}}}{({{p}_{C}})({{p}_{C{{O}_{2}}}})}\] Given,      \[{{p}_{CO}}=8\,atm\] \[{{p}_{C{{O}_{2}}}}=4\,atm\] and for solid\[C(s)\] \[{{P}_{C}}=1\] \[\therefore \] \[{{K}_{p}}=\frac{{{(8)}^{2}}}{1\times 4}\] \[\Rightarrow \] \[{{K}_{p}}=\frac{64}{4}=16\]


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