A) \[I{{O}_{2}}\]
B) \[{{I}_{2}}{{O}_{4}}\]
C) \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]
D) \[\text{HBr}\]
Correct Answer: D
Solution :
\[\left( \frac{1}{1-2i}+\frac{3}{1+i} \right)\left( \frac{3+4i}{2-4i} \right)\] \[=\left[ \frac{1+2i}{{{1}^{2}}+{{2}^{2}}}+\frac{3-3i}{{{1}^{2}}+{{1}^{2}}} \right]\left[ \frac{6-16+12i+8i}{{{2}^{2}}+{{4}^{2}}} \right]\] \[=\left[ \frac{2+4i+15-15i}{10} \right]\left[ \frac{-1+2i}{2} \right]\] \[=\frac{(17-11i)(-1+2i)}{20}\] \[=\frac{5+45i}{20}=\frac{1}{4}+\frac{9}{4}i\]
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