A) \[\sin n\theta =\sum\limits_{r=0}^{n}{{{b}_{r}}{{\sin }^{r}}\theta }\]
B) \[\theta \]
C) \[{{b}_{0}}=0,{{b}_{1}}=3\]
D) \[{{b}_{0}}=1,{{b}_{1}}=n\]
Correct Answer: B
Solution :
Let\[I=\left| \begin{matrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 0 \\ \end{matrix} \right|,\]then \[KI=\left[ \begin{matrix} k & 0 & 0 \\ 0 & k & 0 \\ 0 & 0 & k \\ \end{matrix} \right]\]\[\Rightarrow \]\[adj(kI)=\left[ \begin{matrix} {{k}^{2}} & 0 & 0 \\ 0 & {{k}^{2}} & 0 \\ 0 & 0 & {{k}^{2}} \\ \end{matrix} \right]={{k}^{2}}I\]
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