question_answer

    The angle of depression of a ship from the top of a tower 30 m high is 60°. Then the distance of ship from the base of tower is :

A)  30 m                                    

B)  \[\Delta ABC\]

C)  \[\text{3a}=\text{b}+\text{c}\]                               

D)  10 m

Correct Answer: C

Solution :

                Let RQ be\[x\,m\] from \[\Delta PRQ\] \[tan\text{ }60{}^\circ =\frac{30}{x}\] \[\Rightarrow \]               \[x=10\sqrt{3}m\]