A) \[3\,\,\text{c}{{\text{m}}^{\text{3}}}\text{/s}\]
B) \[2\,\,\text{c}{{\text{m}}^{\text{3}}}\text{/s}\]
C) \[{{E}_{n}}=\frac{-13.6}{{{n}^{2}}}eV\]
D) \[\text{91}0\text{ { }\!\!\mathrm{\AA}\!\!\text{ }},\text{ 1213 { }\!\!\mathrm{\AA}\!\!\text{ }}\]
Correct Answer: B
Solution :
From the formula for energy of photon \[2\,\,\text{c}{{\text{m}}^{\text{3}}}\text{/s}\] \[{{E}_{n}}=\frac{-13.6}{{{n}^{2}}}eV\] \[\text{91}0\text{ { }\!\!\mathrm{\AA}\!\!\text{ }},\text{ 1213 { }\!\!\mathrm{\AA}\!\!\text{ }}\] Hence, \[\text{5463{ }\!\!\mathrm{\AA}\!\!\text{ } },\text{ 7858}{\AA}\] Or \[\text{1315{ }\!\!\mathrm{\AA}\!\!\text{ }},\text{ 153}0{\AA}\] \[\text{5}.\text{67}\times \text{l}{{0}^{\text{7}}}\text{m}/\text{s}\]
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