A) \[x-1\to 0\]
B) \[{{\sec }^{-1}}\frac{1}{2{{x}^{2}}-1}\]
C) \[\sqrt{1-{{x}^{2}}}\]
D) \[x=\frac{1}{2}\]
Correct Answer: C
Solution :
\[\int{\sqrt{1+\sin \frac{x}{2}}}dx\] \[=\int{\sqrt{{{\sin }^{2}}\frac{x}{4}+{{\cos }^{2}}\frac{x}{4}+2\sin \frac{x}{4}\cos \frac{x}{4}}}dx\] \[=\int{\left[ \sin \frac{x}{4}+\cos \frac{x}{4} \right]}dx\] \[=4\left( \sin \frac{x}{4}-\cos \frac{x}{4} \right)+c\]
You need to login to perform this action.
You will be redirected in
3 sec
