JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2004

  • question_answer
        The solution of the differential equation\[\int{\sqrt{1+\sin \frac{x}{2}}}dx\] is :

    A)  \[\frac{1}{4}\left[ \cos \frac{x}{4}-\sin \frac{x}{4} \right]+C\]

    B)  \[4\left[ \cos \frac{x}{4}-\sin \frac{x}{4} \right]+C\]

    C)  \[4\left[ \sin \frac{x}{4}-\cos \frac{x}{4} \right]+C\]

    D)  \[4\left[ \sin \frac{x}{4}+\cos \frac{x}{4} \right]+C\]

    Correct Answer: A

    Solution :

                    \[({{x}^{2}}-y{{x}^{2}})\frac{dy}{dx}+{{y}^{2}}+x{{y}^{2}}=0\] \[\Rightarrow \]               \[\frac{1-y}{{{y}^{2}}}dy+\frac{1+x}{{{x}^{2}}}dx=0\] \[\Rightarrow \]\[\left( \frac{1}{{{y}^{2}}}-\frac{1}{y} \right)dy+\left( \frac{1}{{{x}^{2}}}+\frac{1}{x} \right)dx=0\] On Integra mg, we get                 \[\log \left( \frac{x}{y} \right)=\frac{1}{x}+\frac{1}{y}+c\]


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