A) \[x=4y-2\]
B) \[\frac{8}{9}\]
C) \[\frac{9}{8}\]
D) \[\frac{4}{3}\]
Correct Answer: A
Solution :
Mean\[=up=3,S.D=\sqrt{npq}=\frac{3}{2}\] \[\Rightarrow \] \[q=\frac{npq}{np}\] \[=\frac{9}{4\times 3}=\frac{3}{4}\] \[\Rightarrow \] \[p=1-\frac{3}{4}=\frac{1}{4}\] and \[np=3\Rightarrow n=12\] hence binomial distribution is \[{{(q+p)}^{n}}={{\left( \frac{3}{4}+\frac{1}{4} \right)}^{12}}\]
You need to login to perform this action.
You will be redirected in
3 sec
