JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2004

  • question_answer
        A whistle of frequency 500 Hz, tied to the end of a string of length 1.2 m, revolves at 400 rev/min. A listener standing some distance away in the plane of rotation of whistle hears frequencies in the range of (speed of sound = 340 m/s):

    A)  436 to 386 Hz

    B)  426 to 474 Hz

    C)  426 to 586 Hz

    D)  436 to 586 Hz

    Correct Answer: D

    Solution :

                    \[{{\left[ {{R}^{2}}+{{\left( L\omega -\frac{1}{C\omega } \right)}^{2}} \right]}^{\frac{-1}{2}}}\] \[{{[{{R}^{2}}+{{(L\omega -C\omega )}^{2}}]}^{1/2}}\] \[{{\left[ {{R}^{2}}+{{\left( L\omega -\frac{1}{C\omega } \right)}^{2}} \right]}^{-1/2}}\] \[R\Omega \] \[\text{25}\times \text{1}{{0}^{-\text{3}}}\text{ mH}\] \[\text{5}0\times \text{1}{{0}^{-\text{3}}}\text{H}\] \[\text{5}0\times \text{1}{{0}^{-\text{3}}}\text{mH}\] \[1V\] \[\text{mass}=\text{9}.0\times \text{1}{{0}^{\text{-31}}}\]


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