A) \[\overrightarrow{S}=\left( \text{3\hat{j}}+\text{5\hat{k}} \right)\text{m}\]
B) \[{{\upsilon }_{A}}\]
C) \[{{\upsilon }_{B}}\]
D) \[{{\upsilon }_{A}}:{{\upsilon }_{B}}\]
Correct Answer: A
Solution :
Here : \[{{\upsilon }_{A}}=\tan {{30}^{\circ }}\] Using the relation \[{{\upsilon }_{B}}=\tan {{60}^{\circ }}\] \[\frac{{{\upsilon }_{A}}}{{{\upsilon }_{B}}}=\frac{\tan {{30}^{\circ }}}{\tan {{60}^{\circ }}}\] Or \[=\frac{1/\sqrt{3}}{\sqrt{3}}=\frac{1}{3}\] So \[{{E}_{K}}\left( =\frac{1}{2}m{{\upsilon }^{2}} \right)=\frac{3}{2}KT\] \[{{\text{E}}_{i}}=\text{ 1}0.\text{2 eV }=\text{1}0.\text{2}\times \text{1}.\text{6}\times \text{1}{{0}^{-\text{19}}}\text{ J}\]
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