question_answer

    sp hybridisation is found in :

A) \[[M{{L}^{2}}{{T}^{-2}}{{\theta }^{-1}}]\]                             

B) \[[{{M}^{2}}L{{T}^{-2}}\theta ]\]

C)  \[[M{{L}^{3}}{{T}^{-1}}{{\theta }^{-1}}]\]                            

D)  \[\frac{6}{\sqrt{2}}\]

Correct Answer: D

Solution :

                In \[N{{H}_{3}}\], N undergoes \[\text{s}{{\text{p}}^{\text{3}}}\]hybridisation. Due to the presence of one lone-pair, it is pyramidal in shape.