A) 45 kg
B) 202.5 kg
C) 90 kg
D) 40 kg
Correct Answer: D
Solution :
Acceleration due to gravity on earth is given by \[\frac{m{{\upsilon }^{2}}}{r}=4mg\] \[\therefore \] Hence \[{{\upsilon }^{2}}=4rg\] \[\upsilon =\sqrt{4rg}\] or \[\upsilon =\sqrt{4\times 2.5\times 9.8}\] \[\upsilon =\sqrt{98}\,\,m/s\] Weight of body on moon \[\text{2}0\text{ g }=\text{ 2}\times \text{1}{{0}^{-\text{2}}}\text{ kg},\] \[=\frac{360\times 5}{18}=100m/s\]You need to login to perform this action.
You will be redirected in
3 sec