2. Solved Papers
  3. JAMIA MILLIA ISLAMIA

JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        A plane which passes through the point (3,2,0) and the line\[\frac{x-4}{1}=\frac{y-7}{5}=\frac{z-4}{4}\]is:

    A)  \[x-y+z=1\]                       

    B)  \[x+y+z=5\]

    C)  \[x+2y-z=1\]    

    D)  \[2x-y+z=5\]

    Correct Answer: A

    Solution :

                    Any plane passing through (3, 2, 0) \[a(x-3)+b(y-2)+c(z-0)=0\]                           ?.(i) It passes through (4, 7, 4) Normal to plane (i) is perpendicular to given line \[a+5b+4c=0\]                               ...(ii)                 \[\frac{a}{1}=\frac{b}{-1}=\frac{c}{1}=k\] so           \[a=k,b=-k,c=k\] Putting the value of a, b, c in Eq. (i) we get, \[x-y+z=1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner