JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        The domain of\[{{\sin }^{-1}}[{{\log }_{3}}(x/3)]\]is:

    A)  \[[1,9]\]                             

    B)  \[[-1,9]\]

    C)  \[[-9,1]\]                            

    D)  \[[-9,-1]\]

    Correct Answer: A

    Solution :

                    \[f(x)={{\sin }^{-1}}\left( {{\log }_{3}}\left( \frac{x}{3} \right) \right)\]exists if \[-1\le {{\log }_{3}}\left( \frac{x}{3} \right)\le 1\]\[\Leftrightarrow \]\[{{3}^{-1}}\le \frac{x}{3}\le {{3}^{1}}\] \[\Leftrightarrow \]\[1\le x\le 9\]\[\Leftrightarrow \]domain is [1, 9]


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