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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        The equation of the directrix of the parabola \[{{y}^{2}}+4v+4x+2=0\]is:

    A)  \[x=-1\]                              

    B)  \[x=1\]

    C)  \[x=-\frac{3}{2}\]                           

    D)  \[x=\frac{3}{2}\]

    Correct Answer: D

    Solution :

                     The equation of parabola as \[{{(y+2)}^{2}}=-4\left( x-\frac{1}{2} \right)\] Shifting the origin\[\left( \frac{1}{2},-2 \right),\]the equation of parabola becomes \[{{y}^{2}}=4X\] where \[X=x-\frac{1}{2},Y=y+2\] an equation of its directrix is\[X=1\]required directrix \[x=\frac{3}{2}\]


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