JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2005

  • question_answer
        If\[\left| \begin{matrix}    6i & -3i & 1  \\    4 & 3i & -1  \\    20 & 3 & i  \\ \end{matrix} \right|=x+iy\]then:

    A)  \[x=3,y=1\]       

    B)  \[x=1,y=3\]

    C)  \[x=0,\text{ y}=3\]        

    D)  \[x=0,\text{ }y=0\]

    Correct Answer: D

    Solution :

                    \[x+iy=\left| \begin{matrix}    6i & -3i & 1  \\    4 & 3i & -1  \\    20 & 3 & i  \\ \end{matrix} \right|\] \[x+iy=3i\left| \begin{matrix}    6i & 1 & 1  \\    4 & -1 & -1  \\    20 & i & i  \\ \end{matrix} \right|=0\] \[\Rightarrow \]               \[x+iy=0\] \[\Rightarrow \]               \[x=0,y=0\]


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